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Kirkman’s schoolgirl problem


                                                   Nikolina Marković

                               Center for talented youth Belgrade II, Belgrade, nikolinam98@gmail.com
                                                               so that h−1 must be divisible by k.  if the quotient is marked
          1. Introduction                                      by p, i.e. p =   , after a short transformations we get:

                                                                               v = g ∙ k      (1)
          Kirkman’s  problem  falls  within  the  area  of  so-called
          “recreational  mathematics”  and  it  reads  as  follows:  15   On the fixed and rotating disc, shown in Figure 1, where the
          schoolgirls walk to the school every day in five groups of   triangles  and  dots  are  marked,  we  have  the  solution  for
          three  girls,  it  is  necessary  to  make  a  weekly  schedule  of   v=15.  Indicated  triangles  are  actually  the  required  triplets
          groups so that each pair of schoolgirls is in the same group   and therefore, they can’t be compatible. The initial position
          only  once.  In  order  to  solve  this  and  similar,  practical   where the numbers and dots on both discs overlap, gives the
          problems, it is required the knowledge of the combinatorics   arrangement  of  triplets  for  the  first  day.  The  arrangement
          methods of the finite groups. Solution of the problem leads   for the next six days, we will get by rotating the upper disc
          to the so-called Steiner triple system, named after the works   for the two units in any direction. This means that point 1 at
          of Jacob Steiner. The aim of the present study is to find the   the  rotating  disc  should  coincide  respectively  with  the
          solution for the Kirkman’s problem and its connection with   numbers 3, 5, 7, 9, 11, 13 on the fixed disc (or in reverse
          the block design and Steiner triple system.          order, whatever).


          2. Work methods


          The problem can be solved by research in many different
          ways, but only those types of solutions that are of practical
          and  theoretical  interest  are  those  that  are  based  on  the
          methodology of mathematics. Firstly, we set the algebraic
          conditions  for  the  solution  of  the  problem.  The  second
          approach  is  to  properly  generalize  the  problem  and
          understand it through solving the simple examples. Some of         Figure 1-Solution for v=15
          the solutions are presented by using the fixed and rotating   The most important application of the Kirkman’s problem
          disc. Then, subject to certain rules, we edit a group of 15   is in the development of the basic theory of block designs,
          elements  and  form  triplets.  We  define  a  block  design,   with  which  I  was  occupied  with  in  the  final  part  of  my
          Steiner  triple  system  and  parameters  of  Kirkman’s  triple   paper.
          system.

                                                               4. Conclusion
          3. Research results
                                                               Kirkman’s  schoolgirl  problem  does  not  require  the
          It doesn’t need much to realize that finding the solution is   knowledge of many abstract mathematical methods. For its
          not so trivial.                                      solution,  it  is  necessary  to  know  the  basic  combinatorics
                                                               methods  of  finite  groups,  and  its  implementation  has
          Since  the  number  of  girls  is  positive  integer  v,  and  they,
          according to the conditions of the task, have to walk every   generated the elementary theory of block design.
          day in g rows, where each of them consists of k girls, it is
          obvious that
                                                               5. Literature
                     v = g ∙ k             (1)

          Each  girls  walks  with  k  −  1  different  companion  every  h   [1.] D. Cvetković, S. Simić, Kombinatorika i grafovi,
          days, therefore she walks with each of hers companions v −   Belgrade, 2006
          1. Algebraic expression of this condition is:            [2.] G.  Berman,  K.  D.  Fryer,  Introduction  to
                                                                       Combinatorics, New York-London 1972
                         v − 1 = h       (2)
                                                                   [3.] M.   Petković,   Zanimljivi   problemi   velikih
          From these two equations we get:                             matematičara, Belgrade, 2008
                                                                   [4.] The  Astronomic  Journal,  Cyclic  solutions  of  the
                      g =h −               (3)
                                                                       school-girl puzzle, vol. VI, 1859-1861.
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